How does the impulse experienced by the motorbike compare to its change in momentum? Write only SMALLER THAN, GREATER THAN or EQUAL TO.
About this question
Question 3.5.2 of Technical Sciences Grade 12 Paper 1, NSC Preparatory Examination (Eastern Cape DoE, September 2025). It tests the Term 1 ATP topic Momentum & Impulse Momentum.
- TermTerm 1
- ATP topicMomentum & Impulse Momentum
- PaperPaper 1
- Marks1 mark
A motorbike of mass \(1\,150\ \text{kg}\) crashes into a tree with a velocity of \(15\ \text{m}\cdot\text{s}^{-1}\), as shown in the diagram. The motorbike experiences a constant net force of \(57\,500\ \text{N}\) before it comes to rest.
EQUAL TO
More Questions On Momentum & Impulse Momentum
C: in an isolated system the total linear momentum before the collision is equal to the total linear momentum
In an isolated system the total momentum before a collision equals the total momentum after it.
Compare the total kinetic energy before and after the collision.
\[ \sum E_{ki} = \tfrac{1}{2}(1500)(33{,}33)^2 + \tfrac{1}{2}(1100)(16{,}67)^2 \approx 986\,006\ \text{J} \]\[ \sum E_{kf} = \tfrac{1}{2}(1500)(20{,}3)^2 + \tfrac{1}{2}(1100)(5{,}32)^2 \approx 324\,634\ \text{J} \]\( \sum E_{ki} \neq \sum E_{kf} \), so kinetic energy is not conserved.
The collision is inelastic.
A: \(2mv\) in the opposite direction.
\(\Delta p = m(-v) - mv = -2mv\), so the change is \(2mv\) in the direction opposite to the original motion.
Take the direction towards the tree as negative for the force (it opposes the motion).
\[ F_{net}\Delta t = \Delta p = m(v_f - v_i) \]\[ -57\,500\,\Delta t = 1150(0 - 15) \]\( \Delta t = 0{,}30\ \text{s} \)
\( v_i = 33{,}33\ \text{m}\cdot\text{s}^{-1} \), east